Bug #41732 rpl_ndb_circular_2ch needs an updated configuration file

There are two issues: 
      1. 6.0 uses the obsolate master-*** server options;
      2. the test is not deterministic in that although master vs slave consistency is
         fine, two runs of the test can have different results. The reason of the
         non-determinism is the combination of 
         a chosen way to demo results and the ndb_autoincrement_prefetch_sz feature.

The current patch fixes the 2nd issue by putting out results via diff_table macro
instead of the former run-sensitive method.
The 1st issue is going to be fixed by a separate patch to 6.0.

mysql-test/suite/rpl_ndb/r/rpl_ndb_circular_2ch.result

@@ -45,58 +45,20 @@ CREATE TABLE t1 (a INT NOT NULL AUTO_INCREMENT, b VARCHAR(100), c INT NOT NULL,
 *** Basic testing  ***
 Insert rows via all hosts
 Check data on both clusters 
-* Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 1 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-10	190	master
-10	210	master1
-10	200	slave
-10	220	slave1
-* Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 1 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-10	190	master
-10	210	master1
-10	200	slave
-10	220	slave1
-
+Comparing tables master:test.t1 and slave:test.t1
 *** Transaction testing ***
 BEGIN;
 BEGIN;
 COMMIT;
 COMMIT;
 Check data on both clusters 
-* Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 2 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-100	23900	master
-100	24100	master1
-100	24000	slave
-100	24200	slave1
-* Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 2 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-100	23900	master
-100	24100	master1
-100	24000	slave
-100	24200	slave1
-
+Comparing tables master:test.t1 and slave:test.t1
 BEGIN;
 BEGIN;
 ROLLBACK;
 ROLLBACK;
 Check data on both clusters 
-* Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 3 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-100	64100	master1
-100	64000	slave
-* Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 3 GROUP BY b ORDER BY b;
-COUNT(*)	SUM(a)	b
-100	64100	master1
-100	64000	slave
-
+Comparing tables master:test.t1 and slave:test.t1
 DROP TABLE t1;
 DROP TABLE IF EXISTS t1;
 

mysql-test/suite/rpl_ndb/t/rpl_ndb_circular_2ch.test

@@ -75,13 +75,10 @@ let $wait_condition= SELECT COUNT(*)=40 FROM t1 WHERE c = 1;
 
 # Check data
 --echo Check data on both clusters 
---connection master
---echo * Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 1 GROUP BY b ORDER BY b;
---connection slave
---echo * Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 1 GROUP BY b ORDER BY b;
---echo
+let $diff_table_1=master:test.t1;
+let $diff_table_2=slave:test.t1;
+
+source include/diff_tables.inc;
 
 --echo *** Transaction testing ***
 # Start transaction for one mysqld and do mass of inserts for other.
@@ -119,13 +116,10 @@ let $wait_condition= SELECT COUNT(*)=400 FROM t1 WHERE c = 2;
 --source include/wait_condition.inc
 
 --echo Check data on both clusters 
---connection master
---echo * Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 2 GROUP BY b ORDER BY b;
---connection slave
---echo * Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 2 GROUP BY b ORDER BY b;
---echo
+let $diff_table_1=master:test.t1;
+let $diff_table_2=slave:test.t1;
+
+source include/diff_tables.inc;
 
 # Start transaction and then roll back
 
@@ -161,13 +155,10 @@ let $wait_condition= SELECT COUNT(*)=200 FROM t1 WHERE c = 3;
 --source include/wait_condition.inc
 
 --echo Check data on both clusters 
---connection master
---echo * Cluster A *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 3 GROUP BY b ORDER BY b;
---connection slave
---echo * Cluster B *
-SELECT COUNT(*), SUM(a), b FROM t1 WHERE c = 3 GROUP BY b ORDER BY b;
---echo
+let $diff_table_1=master:test.t1;
+let $diff_table_2=slave:test.t1;
+
+source include/diff_tables.inc;
 
 # Clean up
 --connection master