x86-64, NUMA: Do not scan two times for setup_node_bootmem()

By the time setup_node_bootmem() is called, all the memblocks are
already registered.  As node_data is allocated from these memblocks,
calling it more than once doesn't make any difference.  Drop the loop.

tj: Dropped comment referencing to the old behavior as suggested by
    David and rephrased the description.
Signed-off-by: Yinghai Lu <yinghai@kernel.org>
Acked-by: David Rientjes <rientjes@google.com>
Signed-off-by: Tejun Heo <tj@kernel.org>

arch/x86/mm/numa_64.c

@@ -480,7 +480,7 @@ static bool __init numa_meminfo_cover_memory(const struct numa_meminfo *mi)
 
 static int __init numa_register_memblks(struct numa_meminfo *mi)
 {
-	int i, j, nid;
+	int i, nid;
 
 	/* Account for nodes with cpus and no memory */
 	node_possible_map = numa_nodes_parsed;
@@ -506,29 +506,21 @@ static int __init numa_register_memblks(struct numa_meminfo *mi)
 
 	init_memory_mapping_high();
 
-	/*
-	 * Finally register nodes.  Do it twice in case setup_node_bootmem
-	 * missed one due to missing bootmem.
-	 */
-	for (i = 0; i < 2; i++) {
+	/* Finally register nodes. */
 	for_each_node_mask(nid, node_possible_map) {
 		u64 start = (u64)max_pfn << PAGE_SHIFT;
 		u64 end = 0;
 
-			if (node_online(nid))
-				continue;
-
-			for (j = 0; j < mi->nr_blks; j++) {
-				if (nid != mi->blk[j].nid)
+		for (i = 0; i < mi->nr_blks; i++) {
+			if (nid != mi->blk[i].nid)
 				continue;
-				start = min(mi->blk[j].start, start);
-				end = max(mi->blk[j].end, end);
+			start = min(mi->blk[i].start, start);
+			end = max(mi->blk[i].end, end);
 		}
 
 		if (start < end)
 			setup_node_bootmem(nid, start, end);
 	}
-	}
 
 	return 0;
 }