Commit 4855ff51 authored by unknown's avatar unknown

New tests for prepared statements:

- 'ps_10nestset' uses a "nested set" approach for an employee 
  hierarchy, then does arithmetic on the "salary" field;
  (soon) to be extended by inserts / deletes which imply
  mass updates on the "l"/"r" fields showing the set inclusion,
- 'ps_11bugs' will get (some of ?) those bug DB entries which
  refer to prepared statements, but whose number does not appear
  in a test file comment - so it will also be extended.

parent 9ed05da4
use test;
drop table if exists personnel;
Warnings:
Note 1051 Unknown table 'personnel'
create table personnel (
id INTEGER AUTO_INCREMENT PRIMARY KEY,
emp CHAR(10) NOT NULL,
salary DECIMAL(6,2) NOT NULL,
l INTEGER NOT NULL,
r INTEGER NOT NULL);
prepare st_ins from 'insert into personnel set emp = ?, salary = ?, l = ?, r = ?';
set @arg_nam= 'Jerry';
set @arg_sal= 1000;
set @arg_l= 1;
set @arg_r= 12;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Bert';
set @arg_sal= 900;
set @arg_l= 2;
set @arg_r= 3;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Chuck';
set @arg_sal= 900;
set @arg_l= 4;
set @arg_r= 11;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Donna';
set @arg_sal= 800;
set @arg_l= 5;
set @arg_r= 6;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Eddie';
set @arg_sal= 700;
set @arg_l= 7;
set @arg_r= 8;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Fred';
set @arg_sal= 600;
set @arg_l= 9;
set @arg_r= 10;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
select * from personnel;
id emp salary l r
1 Jerry 1000.00 1 12
2 Bert 900.00 2 3
3 Chuck 900.00 4 11
4 Donna 800.00 5 6
5 Eddie 700.00 7 8
6 Fred 600.00 9 10
prepare st_raise_base from 'update personnel set salary = salary * ( 1 + ? ) where r - l = 1';
prepare st_raise_mgr from 'update personnel set salary = salary + ? where r - l > 1';
set @arg_percent= .10;
set @arg_amount= 100;
execute st_raise_base using @arg_percent;
execute st_raise_mgr using @arg_amount;
execute st_raise_base using @arg_percent;
execute st_raise_mgr using @arg_amount;
execute st_raise_base using @arg_percent;
execute st_raise_mgr using @arg_amount;
select * from personnel;
id emp salary l r
1 Jerry 1300.00 1 12
2 Bert 1197.90 2 3
3 Chuck 1200.00 4 11
4 Donna 1064.80 5 6
5 Eddie 931.70 7 8
6 Fred 798.60 9 10
drop table personnel;
use test;
drop table if exists test_select;
Warnings:
Note 1051 Unknown table 'test_select'
CREATE TABLE test_select(session_id char(9) NOT NULL);
INSERT INTO test_select VALUES ("abc");
SELECT * FROM test_select;
session_id
abc
prepare st_1180 from 'SELECT * FROM test_select WHERE ?="1111" and session_id = "abc"';
set @arg1= 'abc';
execute st_1180 using @arg1;
session_id
set @arg1= '1111';
execute st_1180 using @arg1;
session_id
abc
set @arg1= 'abc';
execute st_1180 using @arg1;
session_id
drop table test_select;
###############################################
# #
# Prepared Statements test on #
# "nested sets" representing hierarchies #
# #
###############################################
# Source: http://kris.koehntopp.de/artikel/sql-self-references (dated 1999)
# Source: http://dbmsmag.com/9603d06.html (dated 1996)
use test;
drop table if exists personnel;
# "Nested Set": This table represents an employee list with a hierarchy tree.
# The tree is not modeled by "parent" links but rather by showing the "left"
# and "right" border of any person's "region". By convention, "l" < "r".
# As it is a tree, these "regions" of two persons A and B are either disjoint,
# or A's region is completely contained in B's (B is A's boss), or vice versa.
# See the references for more info.
create table personnel (
id INTEGER AUTO_INCREMENT PRIMARY KEY,
emp CHAR(10) NOT NULL,
salary DECIMAL(6,2) NOT NULL,
l INTEGER NOT NULL,
r INTEGER NOT NULL);
prepare st_ins from 'insert into personnel set emp = ?, salary = ?, l = ?, r = ?';
# Initial employee list:
# Jerry ( Bert ( ) Chuck ( Donna ( ) Eddie ( ) Fred ( ) ) )
set @arg_nam= 'Jerry'; set @arg_sal= 1000; set @arg_l= 1; set @arg_r= 12;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Bert'; set @arg_sal= 900; set @arg_l= 2; set @arg_r= 3;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Chuck'; set @arg_sal= 900; set @arg_l= 4; set @arg_r= 11;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Donna'; set @arg_sal= 800; set @arg_l= 5; set @arg_r= 6;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Eddie'; set @arg_sal= 700; set @arg_l= 7; set @arg_r= 8;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
set @arg_nam= 'Fred'; set @arg_sal= 600; set @arg_l= 9; set @arg_r= 10;
execute st_ins using @arg_nam, @arg_sal, @arg_l, @arg_r ;
select * from personnel;
# Three successive raises, each one is 100 units for managers, 10 percent for others.
prepare st_raise_base from 'update personnel set salary = salary * ( 1 + ? ) where r - l = 1';
prepare st_raise_mgr from 'update personnel set salary = salary + ? where r - l > 1';
let $1= 3;
set @arg_percent= .10;
set @arg_amount= 100;
while ($1)
{
execute st_raise_base using @arg_percent;
execute st_raise_mgr using @arg_amount;
dec $1;
}
select * from personnel;
drop table personnel;
###############################################
# #
# Prepared Statements #
# re-testing bug DB entries #
# #
###############################################
use test;
# bug#1180: optimized away part of WHERE clause cause incorect prepared satatement results
drop table if exists test_select;
CREATE TABLE test_select(session_id char(9) NOT NULL);
INSERT INTO test_select VALUES ("abc");
SELECT * FROM test_select;
prepare st_1180 from 'SELECT * FROM test_select WHERE ?="1111" and session_id = "abc"';
# Must not find a row
set @arg1= 'abc';
execute st_1180 using @arg1;
# Now, it should find one row
set @arg1= '1111';
execute st_1180 using @arg1;
# Back to non-matching
set @arg1= 'abc';
execute st_1180 using @arg1;
drop table test_select;
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