ss: Drop silly assignment

An expression of the form '(a | b) & b' will evaluate to the value of b
for any value of a or b.
Signed-off-by: Phil Sutter <phil@nwl.cc>

misc/ss.c

@@ -267,7 +267,7 @@ static void filter_default_dbs(struct filter *f)
 static void filter_states_set(struct filter *f, int states)
 {
 	if (states)
-		f->states = (f->states | states) & states;
+		f->states = states;
 }
 
 static void filter_merge_defaults(struct filter *f)