watchdog: gef: Convert to platform remove callback returning void

The .remove() callback for a platform driver returns an int which makes
many driver authors wrongly assume it's possible to do error handling by
returning an error code. However the value returned is (mostly) ignored
and this typically results in resource leaks. To improve here there is a
quest to make the remove callback return void. In the first step of this
quest all drivers are converted to .remove_new() which already returns
void.

Trivially convert this driver from always returning zero in the remove
callback to the void returning variant.
Signed-off-by: Uwe Kleine-König <u.kleine-koenig@pengutronix.de>
Reviewed-by: Guenter Roeck <linux@roeck-us.net>
Link: https://lore.kernel.org/r/20230303213716.2123717-13-u.kleine-koenig@pengutronix.deSigned-off-by: Guenter Roeck <linux@roeck-us.net>
Signed-off-by: Wim Van Sebroeck <wim@linux-watchdog.org>

drivers/watchdog/gef_wdt.c

@@ -283,15 +283,13 @@ static int gef_wdt_probe(struct platform_device *dev)
 	return misc_register(&gef_wdt_miscdev);
 }
 
-static int gef_wdt_remove(struct platform_device *dev)
+static void gef_wdt_remove(struct platform_device *dev)
 {
 	misc_deregister(&gef_wdt_miscdev);
 
 	gef_wdt_handler_disable();
 
 	iounmap(gef_wdt_regs);
-
-	return 0;
 }
 
 static const struct of_device_id gef_wdt_ids[] = {
@@ -308,7 +306,7 @@ static struct platform_driver gef_wdt_driver = {
 		.of_match_table = gef_wdt_ids,
 	},
 	.probe		= gef_wdt_probe,
-	.remove		= gef_wdt_remove,
+	.remove_new	= gef_wdt_remove,
 };
 
 static int __init gef_wdt_init(void)