Skip to content
Projects
Groups
Snippets
Help
Loading...
Help
Support
Keyboard shortcuts
?
Submit feedback
Contribute to GitLab
Sign in / Register
Toggle navigation
M
mariadb
Project overview
Project overview
Details
Activity
Releases
Repository
Repository
Files
Commits
Branches
Tags
Contributors
Graph
Compare
Issues
0
Issues
0
List
Boards
Labels
Milestones
Merge Requests
0
Merge Requests
0
Analytics
Analytics
Repository
Value Stream
Wiki
Wiki
Snippets
Snippets
Members
Members
Collapse sidebar
Close sidebar
Activity
Graph
Create a new issue
Commits
Issue Boards
Open sidebar
Kirill Smelkov
mariadb
Commits
0d40608f
Commit
0d40608f
authored
Feb 01, 2007
by
gkodinov/kgeorge@rakia.gmz
Browse files
Options
Browse Files
Download
Plain Diff
Merge gkodinov@bk-internal.mysql.com:/home/bk/mysql-5.0-opt
into rakia.gmz:/home/kgeorge/mysql/autopush/B25551-5.0-opt
parents
71013621
2ba683f2
Changes
3
Hide whitespace changes
Inline
Side-by-side
Showing
3 changed files
with
52 additions
and
10 deletions
+52
-10
mysql-test/r/distinct.result
mysql-test/r/distinct.result
+25
-1
mysql-test/t/distinct.test
mysql-test/t/distinct.test
+16
-1
sql/sql_select.cc
sql/sql_select.cc
+11
-8
No files found.
mysql-test/r/distinct.result
View file @
0d40608f
...
...
@@ -530,7 +530,8 @@ id select_type table type possible_keys key key_len ref rows Extra
EXPLAIN SELECT DISTINCT a,b FROM t1 GROUP BY a,b;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 3
CREATE TABLE t2(a INT, b INT, c INT, d INT, PRIMARY KEY (a,b));
CREATE TABLE t2(a INT, b INT NOT NULL, c INT NOT NULL, d INT,
PRIMARY KEY (a,b));
INSERT INTO t2 VALUES (1,1,1,50), (1,2,3,40), (2,1,3,4);
EXPLAIN SELECT DISTINCT a FROM t2;
id select_type table type possible_keys key key_len ref rows Extra
...
...
@@ -644,3 +645,26 @@ SELECT COUNT(*) FROM
COUNT(*)
2
DROP TABLE t1, t2;
CREATE TABLE t1 (a INT, UNIQUE (a));
INSERT INTO t1 VALUES (4),(null),(2),(1),(null),(3);
EXPLAIN SELECT DISTINCT a FROM t1;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 index NULL a 5 NULL 6 Using index
SELECT DISTINCT a FROM t1;
a
NULL
1
2
3
4
EXPLAIN SELECT a FROM t1 GROUP BY a;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE t1 index NULL a 5 NULL 6 Using index
SELECT a FROM t1 GROUP BY a;
a
NULL
1
2
3
4
DROP TABLE t1;
mysql-test/t/distinct.test
View file @
0d40608f
...
...
@@ -364,7 +364,8 @@ EXPLAIN SELECT a FROM t1 GROUP BY a;
EXPLAIN
SELECT
a
,
b
FROM
t1
GROUP
BY
a
,
b
;
EXPLAIN
SELECT
DISTINCT
a
,
b
FROM
t1
GROUP
BY
a
,
b
;
CREATE
TABLE
t2
(
a
INT
,
b
INT
,
c
INT
,
d
INT
,
PRIMARY
KEY
(
a
,
b
));
CREATE
TABLE
t2
(
a
INT
,
b
INT
NOT
NULL
,
c
INT
NOT
NULL
,
d
INT
,
PRIMARY
KEY
(
a
,
b
));
INSERT
INTO
t2
VALUES
(
1
,
1
,
1
,
50
),
(
1
,
2
,
3
,
40
),
(
2
,
1
,
3
,
4
);
EXPLAIN
SELECT
DISTINCT
a
FROM
t2
;
EXPLAIN
SELECT
DISTINCT
a
,
a
FROM
t2
;
...
...
@@ -525,3 +526,17 @@ SELECT COUNT(*) FROM
(
SELECT
DISTINCT
a
FROM
t2
WHERE
a
=
'oe'
COLLATE
latin1_german2_ci
)
dt
;
DROP
TABLE
t1
,
t2
;
#
# Bug #25551: inconsistent behaviour in grouping NULL, depending on index type
#
CREATE
TABLE
t1
(
a
INT
,
UNIQUE
(
a
));
INSERT
INTO
t1
VALUES
(
4
),(
null
),(
2
),(
1
),(
null
),(
3
);
EXPLAIN
SELECT
DISTINCT
a
FROM
t1
;
#result must have one row with NULL
SELECT
DISTINCT
a
FROM
t1
;
EXPLAIN
SELECT
a
FROM
t1
GROUP
BY
a
;
#result must have one row with NULL
SELECT
a
FROM
t1
GROUP
BY
a
;
DROP
TABLE
t1
;
sql/sql_select.cc
View file @
0d40608f
...
...
@@ -873,10 +873,11 @@ JOIN::optimize()
}
/*
Check if we can optimize away GROUP BY/DISTINCT.
We can do that if there are no aggregate functions
and
the
We can do that if there are no aggregate functions
,
the
fields in DISTINCT clause (if present) and/or columns in GROUP BY
(if present) contain direct references to all key parts of
an unique index (in whatever order).
an unique index (in whatever order) and if the key parts of the
unique index cannot contain NULLs.
Note that the unique keys for DISTINCT and GROUP BY should not
be the same (as long as they are unique).
...
...
@@ -11896,7 +11897,7 @@ test_if_subkey(ORDER *order, TABLE *table, uint ref, uint ref_key_parts,
/*
Check if GROUP BY/DISTINCT can be optimized away because the set is
Check if GROUP BY/DISTINCT can be optimized away because the set is
already known to be distinct.
SYNOPSIS
...
...
@@ -11904,7 +11905,7 @@ test_if_subkey(ORDER *order, TABLE *table, uint ref, uint ref_key_parts,
table The table to operate on.
find_func function to iterate over the list and search
for a field
DESCRIPTION
Used in removing the GROUP BY/DISTINCT of the following types of
statements:
...
...
@@ -11915,12 +11916,13 @@ test_if_subkey(ORDER *order, TABLE *table, uint ref, uint ref_key_parts,
then <any combination of a,b,c>,{whatever} is also distinct
This function checks if all the key parts of any of the unique keys
of the table are referenced by a list : either the select list
of the table are referenced by a list : either the select list
through find_field_in_item_list or GROUP BY list through
find_field_in_order_list.
If the above holds then we can safely remove the GROUP BY/DISTINCT,
If the above holds and the key parts cannot contain NULLs then we
can safely remove the GROUP BY/DISTINCT,
as no result set can be more distinct than an unique key.
RETURN VALUE
1 found
0 not found.
...
...
@@ -11943,7 +11945,8 @@ list_contains_unique_index(TABLE *table,
key_part
<
key_part_end
;
key_part
++
)
{
if
(
!
find_func
(
key_part
->
field
,
data
))
if
(
key_part
->
field
->
maybe_null
()
||
!
find_func
(
key_part
->
field
,
data
))
break
;
}
if
(
key_part
==
key_part_end
)
...
...
Write
Preview
Markdown
is supported
0%
Try again
or
attach a new file
Attach a file
Cancel
You are about to add
0
people
to the discussion. Proceed with caution.
Finish editing this message first!
Cancel
Please
register
or
sign in
to comment