Commit b3cd49f3 authored by unknown's avatar unknown

fixed problem with distinct select with grouping and subqueries (BUG#7946)


mysql-test/r/derived.result:
  DISTINCT over grouped select on subquery in the FROM clause
mysql-test/t/derived.test:
  DISTINCT over grouped select on subquery in the FROM clause
sql/sql_select.cc:
  used current join copy for test
parent 0a8852c3
......@@ -330,3 +330,12 @@ SELECT MIN(price) min, MAX(price) max, AVG(price) avg FROM (SELECT SUBSTRING( MA
min max avg
10.00 10.00 10
DROP TABLE t1;
create table t1 (a integer, b integer);
insert into t1 values (1,4), (2,2),(2,2), (4,1),(4,1),(4,1),(4,1);
select distinct sum(b) from t1 group by a;
sum(b)
4
select distinct sum(b) from (select a,b from t1) y group by a;
sum(b)
4
drop table t1;
......@@ -214,3 +214,13 @@ CREATE TABLE `t1` ( `itemid` int(11) NOT NULL default '0', `grpid` varchar(15) N
insert into t1 values (128, 'rozn', 2, now(), 10),(128, 'rozn', 1, now(), 10);
SELECT MIN(price) min, MAX(price) max, AVG(price) avg FROM (SELECT SUBSTRING( MAX(concat(date_,";",price)), 12) price FROM t1 WHERE itemid=128 AND grpid='rozn' GROUP BY itemid, grpid, vendor) lastprices;
DROP TABLE t1;
#
# DISTINCT over grouped select on subquery in the FROM clause
#
create table t1 (a integer, b integer);
insert into t1 values (1,4), (2,2),(2,2), (4,1),(4,1),(4,1),(4,1);
select distinct sum(b) from t1 group by a;
select distinct sum(b) from (select a,b from t1) y group by a;
drop table t1;
......@@ -1304,7 +1304,7 @@ JOIN::exec()
curr_join->select_distinct=0; /* Each row is unique */
curr_join->join_free(0); /* Free quick selects */
if (select_distinct && ! group_list)
if (curr_join->select_distinct && ! curr_join->group_list)
{
thd->proc_info="Removing duplicates";
if (curr_join->tmp_having)
......
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