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David Herrmann authored
After we successfully registered a socket via bt_sock_register() there is no reason to ever check the return code of bt_sock_unregister(). If bt_sock_unregister() fails, it means the socket _is_ already unregistered so we have what we want, don't we? Also, to get bt_sock_unregister() to fail, another part of the kernel has to unregister _our_ socket. This is sooo _wrong_ that it will break way earlier than when we unregister our socket. Signed-off-by: David Herrmann <dh.herrmann@gmail.com> Signed-off-by: Gustavo Padovan <gustavo.padovan@collabora.co.uk>
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