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Ingo Molnar authored
So the current code uses fpu->has_cpu to determine whether a given user FPU context is actively loaded into the FPU's registers [*] and that those registers represent the task's current FPU state. But this term is not unambiguous: especially the distinction between fpu->has_fpu, PF_USED_MATH and fpu_fpregs_owner_ctx is not clear. Increase clarity by unambigously signalling that it's about hardware registers being active right now, by renaming it to fpu->fpregs_active. ( In later patches we'll use more of the 'fpregs' naming, which will make it easier to grep for as well. ) [*] There's the kernel_fpu_begin()/end() primitive that also activates FPU hw registers as well and uses them, without touching the fpu->fpregs_active flag. Reviewed-by: Borislav Petkov <bp@alien8.de> Cc: Andy Lutomirski <luto@amacapital.net> Cc: Dave Hansen <dave.hansen@linux.intel.com> Cc: Fenghua Yu <fenghua.yu@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Ingo Molnar <mingo@kernel.org>
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