i40e/i40evf: bump tail only in multiples of 8
Hardware only fetches descriptors on cachelines of 8, essentially ignoring the lower 3 bits of the tail register. Thus, it is pointless to bump tail by an unaligned access as the hardware will ignore some of the new descriptors we allocated. Thus, it's ideal if we can ensure tail writes are always aligned to 8. At first, it seems like we'd already do this, since we allocate descriptors in batches which are a multiple of 8. Since we'd always increment by a multiple of 8, it seems like the value should always be aligned. However, this ignores allocation failures. If we fail to allocate a buffer, our tail register will become unaligned. Once it has become unaligned it will essentially be stuck unaligned until a buffer allocation happens to fail at the exact amount necessary to re-align it. We can do better, by simply rounding down the number of buffers we're about to allocate (cleaned_count) such that "next_to_clean + cleaned_count" is rounded to the nearest multiple of 8. We do this by calculating how far off that value is and subtracting it from the cleaned_count. This essentially defers allocation of buffers if they're going to be ignored by hardware anyways, and re-aligns our next_to_use and tail values after a failure to allocate a descriptor. This calculation ensures that we always align the tail writes in a way the hardware expects and don't unnecessarily allocate buffers which won't be fetched immediately. Signed-off-by: Jacob Keller <jacob.e.keller@intel.com> Tested-by: Andrew Bowers <andrewx.bowers@intel.com> Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
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