lib/vsprintf.c: eliminate duplicate hex string array

gcc doesn't merge or overlap const char[] objects with identical contents
(probably language lawyers would also insist that these things have
different addresses), but there's no reason to have the string
"0123456789ABCDEF" occur in multiple places.  hex_asc_upper is declared in
kernel.h and defined in lib/hexdump.c, which is unconditionally compiled
in.
Signed-off-by: Rasmus Villemoes <linux@rasmusvillemoes.dk>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Tejun Heo <tj@kernel.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

lib/vsprintf.c

@@ -383,9 +383,6 @@ static noinline_for_stack
 char *number(char *buf, char *end, unsigned long long num,
 	     struct printf_spec spec)
 {
-	/* we are called with base 8, 10 or 16, only, thus don't need "G..."  */
-	static const char digits[16] = "0123456789ABCDEF"; /* "GHIJKLMNOPQRSTUVWXYZ"; */
-
 	char tmp[3 * sizeof(num)];
 	char sign;
 	char locase;
@@ -422,7 +419,7 @@ char *number(char *buf, char *end, unsigned long long num,
 	/* generate full string in tmp[], in reverse order */
 	i = 0;
 	if (num < spec.base)
-		tmp[i++] = digits[num] | locase;
+		tmp[i++] = hex_asc_upper[num] | locase;
 	else if (spec.base != 10) { /* 8 or 16 */
 		int mask = spec.base - 1;
 		int shift = 3;
@@ -430,7 +427,7 @@ char *number(char *buf, char *end, unsigned long long num,
 		if (spec.base == 16)
 			shift = 4;
 		do {
-			tmp[i++] = (digits[((unsigned char)num) & mask] | locase);
+			tmp[i++] = (hex_asc_upper[((unsigned char)num) & mask] | locase);
 			num >>= shift;
 		} while (num);
 	} else { /* base 10 */