Revert "TPM: Long default timeout fix"

This reverts commit c4ff4b82.

Ted Ts'o reports:

 "TPM is working for me so I can log into employer's network in 2.6.37.
  It broke when I tried 2.6.38-rc6, with the following relevant lines
  from my dmesg:

  [   11.081627] tpm_tis 00:0b: 1.2 TPM (device-id 0x0, rev-id 78)
  [   25.734114] tpm_tis 00:0b: Operation Timed out
  [   78.040949] tpm_tis 00:0b: Operation Timed out

  This caused me to get suspicious, especially since the _other_ TPM
  commit in 2.6.38 had already been reverted, so I tried reverting
  commit c4ff4b82: "TPM: Long default timeout fix".  With this commit
  reverted, my TPM on my Lenovo T410 is once again working."
Requested-and-tested-by: Theodore Ts'o <tytso@mit.edu>
Acked-by: Rajiv Andrade <srajiv@linux.vnet.ibm.com>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

drivers/char/tpm/tpm.c

@@ -364,14 +364,12 @@ unsigned long tpm_calc_ordinal_duration(struct tpm_chip *chip,
 		    tpm_protected_ordinal_duration[ordinal &
 						   TPM_PROTECTED_ORDINAL_MASK];
 
-	if (duration_idx != TPM_UNDEFINED) {
+	if (duration_idx != TPM_UNDEFINED)
 		duration = chip->vendor.duration[duration_idx];
-		/* if duration is 0, it's because chip->vendor.duration wasn't */
-		/* filled yet, so we set the lowest timeout just to give enough */
-		/* time for tpm_get_timeouts() to succeed */
-		return (duration <= 0 ? HZ : duration);
-	} else
+	if (duration <= 0)
 		return 2 * 60 * HZ;
+	else
+		return duration;
 }
 EXPORT_SYMBOL_GPL(tpm_calc_ordinal_duration);