ext4: convert swap_inode_data() over to use swap() on most of the fields

For some odd reason, it forces a byte-by-byte copy of each field. A
plain old swap() on most of these fields would be more efficient. We
do need to retain the memswap of i_data however as that field is an array.
Signed-off-by: Theodore Ts'o <tytso@mit.edu>
Signed-off-by: Jeff Layton <jlayton@redhat.com>
Reviewed-by: Jan Kara <jack@suse.cz>

fs/ext4/ioctl.c

@@ -64,18 +64,16 @@ static void swap_inode_data(struct inode *inode1, struct inode *inode2)
 	ei1 = EXT4_I(inode1);
 	ei2 = EXT4_I(inode2);
 
-	memswap(&inode1->i_flags, &inode2->i_flags, sizeof(inode1->i_flags));
-	memswap(&inode1->i_version, &inode2->i_version,
-		  sizeof(inode1->i_version));
-	memswap(&inode1->i_blocks, &inode2->i_blocks,
-		  sizeof(inode1->i_blocks));
-	memswap(&inode1->i_bytes, &inode2->i_bytes, sizeof(inode1->i_bytes));
-	memswap(&inode1->i_atime, &inode2->i_atime, sizeof(inode1->i_atime));
-	memswap(&inode1->i_mtime, &inode2->i_mtime, sizeof(inode1->i_mtime));
+	swap(inode1->i_flags, inode2->i_flags);
+	swap(inode1->i_version, inode2->i_version);
+	swap(inode1->i_blocks, inode2->i_blocks);
+	swap(inode1->i_bytes, inode2->i_bytes);
+	swap(inode1->i_atime, inode2->i_atime);
+	swap(inode1->i_mtime, inode2->i_mtime);
 
 	memswap(ei1->i_data, ei2->i_data, sizeof(ei1->i_data));
-	memswap(&ei1->i_flags, &ei2->i_flags, sizeof(ei1->i_flags));
-	memswap(&ei1->i_disksize, &ei2->i_disksize, sizeof(ei1->i_disksize));
+	swap(ei1->i_flags, ei2->i_flags);
+	swap(ei1->i_disksize, ei2->i_disksize);
 	ext4_es_remove_extent(inode1, 0, EXT_MAX_BLOCKS);
 	ext4_es_remove_extent(inode2, 0, EXT_MAX_BLOCKS);