ice: Remove unnecessary wait when disabling/enabling Rx queues

In ice_vsi_ctrl_rx_rings() we are unnecessarily waiting for
QRX_CTRL_QENA_REQ and QRX_CTRL_QENA_STAT to be the same value prior to
disabling each Rx queue. There is no reason to do this so remove
this wait loop as we already have a wait loop after disabling/enabling
the Rx queue through the QRX_CTRL register to make sure it gets
successfully disabled/enabled.
Signed-off-by: Brett Creeley <brett.creeley@intel.com>
Signed-off-by: Anirudh Venkataramanan <anirudh.venkataramanan@intel.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>

drivers/net/ethernet/intel/ice/ice_lib.c

@@ -197,19 +197,13 @@ static int ice_vsi_ctrl_rx_rings(struct ice_vsi *vsi, bool ena)
 {
 	struct ice_pf *pf = vsi->back;
 	struct ice_hw *hw = &pf->hw;
-	int i, j, ret = 0;
+	int i, ret = 0;
 
 	for (i = 0; i < vsi->num_rxq; i++) {
 		int pf_q = vsi->rxq_map[i];
 		u32 rx_reg;
 
-		for (j = 0; j < ICE_Q_WAIT_MAX_RETRY; j++) {
-			rx_reg = rd32(hw, QRX_CTRL(pf_q));
-			if (((rx_reg >> QRX_CTRL_QENA_REQ_S) & 1) ==
-			    ((rx_reg >> QRX_CTRL_QENA_STAT_S) & 1))
-				break;
-			usleep_range(1000, 2000);
-		}
+		rx_reg = rd32(hw, QRX_CTRL(pf_q));
 
 		/* Skip if the queue is already in the requested state */
 		if (ena == !!(rx_reg & QRX_CTRL_QENA_STAT_M))