1. 24 Nov, 2017 5 commits
  2. 23 Nov, 2017 5 commits
  3. 22 Nov, 2017 4 commits
  4. 21 Nov, 2017 11 commits
  5. 20 Nov, 2017 4 commits
  6. 19 Nov, 2017 1 commit
  7. 18 Nov, 2017 1 commit
  8. 17 Nov, 2017 3 commits
  9. 16 Nov, 2017 6 commits
    • Vladislav Vaintroub's avatar
      Fix rocksdb tests on Windows · 0d1e805a
      Vladislav Vaintroub authored
      0d1e805a
    • Vladislav Vaintroub's avatar
      MDEV-13852 - redefine WinWriteableFile such as IsSyncThreadSafe() · 689168be
      Vladislav Vaintroub authored
      is set to true, as it should.
      
      Copy and modify original io_win.h header file to a different location
      (as we cannot patch anything in submodule). Make sure modified header is
      used.
      689168be
    • Alexey Botchkov's avatar
      MDEV-14402 JSON_VALUE doesn't escape quote. · 842dce37
      Alexey Botchkov authored
              Result unescaping added.
      842dce37
    • Jan Lindström's avatar
      MDEV-9663: InnoDB assertion failure: *cursor->index->name == TEMP_INDEX_PREFIX · d7349e20
      Jan Lindström authored
      MariaDB adjustments to test case innodb-replace-debug and
      add missing instrumentation to row0ins.cc.
      
      MariaDB 10.1 does not seem to be affected.
      d7349e20
    • Jan Lindström's avatar
      MDEV-9663: InnoDB assertion failure: *cursor->index->name == TEMP_INDEX_PREFIX · eeec64d7
      Jan Lindström authored
      Imported missing test case from MySQL 5.7 for
      
      commit 25781c154396dbbc21023786aa3be070057d6999
      Author: Annamalai Gurusami <annamalai.gurusami@oracle.com>
      Date:   Mon Feb 24 14:00:03 2014 +0530
      
          Bug #17604730 ASSERTION: *CURSOR->INDEX->NAME == TEMP_INDEX_PREFIX
      eeec64d7
    • Jan Lindström's avatar
      MDEV-13206: INSERT ON DUPLICATE KEY UPDATE foreign key fail · 0c4d11e8
      Jan Lindström authored
      This is caused by following change:
      
      commit 95d29c99f01882ffcc2259f62b3163f9b0e80c75
      Author: Marko Mäkelä <marko.makela@oracle.com>
      Date:   Tue Nov 27 11:12:13 2012 +0200
      
          Bug#15920445 INNODB REPORTS ER_DUP_KEY BEFORE CREATE UNIQUE INDEX COMPLETED
      
          There is a phase during online secondary index creation where the index has
          been internally completed inside InnoDB, but does not 'officially' exist yet.
          We used to report ER_DUP_KEY in these situations, like this:
      
          ERROR 23000: Can't write; duplicate key in table 't1'
      
          What we should do is to let the 'offending' operation complete, but report an
          error to the
          ALTER TABLE t1 ADD UNIQUE KEY (c2):
      
          ERROR HY000: Index c2 is corrupted
          (This misleading error message should be fixed separately:
          Bug#15920713 CREATE UNIQUE INDEX REPORTS ER_INDEX_CORRUPT INSTEAD OF DUPLICATE)
      
          row_ins_sec_index_entry_low(): flag the index corrupted instead of
          reporting a duplicate, in case the index has not been published yet.
      
          rb:1614 approved by Jimmy Yang
      
      Problem is that after we have found duplicate key on primary key
      we continue to get necessary gap locks in secondary indexes to
      block concurrent transactions from inserting the searched records.
      However, search from unique index used in foreign key constraint
      could return DB_NO_REFERENCED_ROW if INSERT .. ON DUPLICATE KEY UPDATE
      does not contain value for foreign key column. In this case
      we should return the original DB_DUPLICATE_KEY error instead
      of DB_NO_REFERENCED_ROW.
      
      Consider as a example following:
      
      create table child(a int not null primary key,
      b int not null,
      c int,
      unique key (b),
      foreign key (b) references
      parent (id)) engine=innodb;
      
      insert into child values (1,1,2);
      
      insert into child(a) values (1) on duplicate key update c = 3;
      
      Now primary key value 1 naturally causes duplicate key error that will be
      stored on node->duplicate. If there was no duplicate key error, we should
      return the actual no referenced row error. As value for column b used in
      both unique key and foreign key is not provided, server uses 0 as a
      search value. This is naturally, not found leading to DB_NO_REFERENCED_ROW.
      But, we should update the row with primay key value 1 anyway as
      requested by on duplicate key update clause.
      0c4d11e8