When allocating a delalloc work we are always setting the delayed_iput
to 0. So remove the delay_iput member of btrfs_delalloc_work, as a
result also remove it as a parameter from btrfs_alloc_delalloc_work
since it's not used anymore.
Signed-off-by: Nikolay Borisov <nborisov@suse.com>
Reviewed-by: Qu Wenruo <wqu@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>