Commit 751b1710 authored by Julian Wiedmann's avatar Julian Wiedmann Committed by Paul E. McKenney

rculist: Unify documentation about missing list_empty_rcu()

We have two separate sections that talk about why list_empty_rcu()
is not needed, so this commit consolidates them.
Signed-off-by: default avatarJulian Wiedmann <jwi@linux.ibm.com>
[ paulmck: The usual wordsmithing. ]
Signed-off-by: default avatarPaul E. McKenney <paulmck@kernel.org>
parent 5fcb3a5f
......@@ -10,15 +10,6 @@
#include <linux/list.h>
#include <linux/rcupdate.h>
/*
* Why is there no list_empty_rcu()? Because list_empty() serves this
* purpose. The list_empty() function fetches the RCU-protected pointer
* and compares it to the address of the list head, but neither dereferences
* this pointer itself nor provides this pointer to the caller. Therefore,
* it is not necessary to use rcu_dereference(), so that list_empty() can
* be used anywhere you would want to use a list_empty_rcu().
*/
/*
* INIT_LIST_HEAD_RCU - Initialize a list_head visible to RCU readers
* @list: list to be initialized
......@@ -318,21 +309,29 @@ static inline void list_splice_tail_init_rcu(struct list_head *list,
/*
* Where are list_empty_rcu() and list_first_entry_rcu()?
*
* Implementing those functions following their counterparts list_empty() and
* list_first_entry() is not advisable because they lead to subtle race
* conditions as the following snippet shows:
* They do not exist because they would lead to subtle race conditions:
*
* if (!list_empty_rcu(mylist)) {
* struct foo *bar = list_first_entry_rcu(mylist, struct foo, list_member);
* do_something(bar);
* }
*
* The list may not be empty when list_empty_rcu checks it, but it may be when
* list_first_entry_rcu rereads the ->next pointer.
*
* Rereading the ->next pointer is not a problem for list_empty() and
* list_first_entry() because they would be protected by a lock that blocks
* writers.
* The list might be non-empty when list_empty_rcu() checks it, but it
* might have become empty by the time that list_first_entry_rcu() rereads
* the ->next pointer, which would result in a SEGV.
*
* When not using RCU, it is OK for list_first_entry() to re-read that
* pointer because both functions should be protected by some lock that
* blocks writers.
*
* When using RCU, list_empty() uses READ_ONCE() to fetch the
* RCU-protected ->next pointer and then compares it to the address of the
* list head. However, it neither dereferences this pointer nor provides
* this pointer to its caller. Thus, READ_ONCE() suffices (that is,
* rcu_dereference() is not needed), which means that list_empty() can be
* used anywhere you would want to use list_empty_rcu(). Just don't
* expect anything useful to happen if you do a subsequent lockless
* call to list_first_entry_rcu()!!!
*
* See list_first_or_null_rcu for an alternative.
*/
......
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