x86: Simplify __HAVE_ARCH_CMPXCHG tests
Both the 32-bit and 64-bit cmpxchg.h header define __HAVE_ARCH_CMPXCHG and there's ifdeffery which checks it. But since both bitness define it, we can just as well move it up to the main cmpxchg header and simpify a bit of code in doing that. Signed-off-by: Borislav Petkov <bp@suse.de> Link: http://lkml.kernel.org/r/20140711104338.GB17083@pd.tnicSigned-off-by: H. Peter Anvin <hpa@linux.intel.com>
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