Commit c8765de0 authored by Paolo Valente's avatar Paolo Valente Committed by Jens Axboe

blok, bfq: do not plug I/O if all queues are weight-raised

To reduce latency for interactive and soft real-time applications, bfq
privileges the bfq_queues containing the I/O of these
applications. These privileged queues, referred-to as weight-raised
queues, get a much higher share of the device throughput
w.r.t. non-privileged queues. To preserve this higher share, the I/O
of any non-weight-raised queue must be plugged whenever a sync
weight-raised queue, while being served, remains temporarily empty. To
attain this goal, bfq simply plugs any I/O (from any queue), if a sync
weight-raised queue remains empty while in service.

Unfortunately, this plugging typically lowers throughput with random
I/O, on devices with internal queueing (because it reduces the filling
level of the internal queues of the device).

This commit addresses this issue by restricting the cases where
plugging is performed: if a sync weight-raised queue remains empty
while in service, then I/O plugging is performed only if some of the
active bfq_queues are *not* weight-raised (which is actually the only
circumstance where plugging is needed to preserve the higher share of
the throughput of weight-raised queues). This restriction proved able
to boost throughput in really many use cases needing only maximum
throughput.
Signed-off-by: default avatarPaolo Valente <paolo.valente@linaro.org>
Signed-off-by: default avatarJens Axboe <axboe@kernel.dk>
parent d0edc247
...@@ -3580,7 +3580,12 @@ static bool bfq_better_to_idle(struct bfq_queue *bfqq) ...@@ -3580,7 +3580,12 @@ static bool bfq_better_to_idle(struct bfq_queue *bfqq)
* whether bfqq is being weight-raised, because * whether bfqq is being weight-raised, because
* bfq_symmetric_scenario() does not take into account also * bfq_symmetric_scenario() does not take into account also
* weight-raised queues (see comments on * weight-raised queues (see comments on
* bfq_weights_tree_add()). * bfq_weights_tree_add()). In particular, if bfqq is being
* weight-raised, it is important to idle only if there are
* other, non-weight-raised queues that may steal throughput
* to bfqq. Actually, we should be even more precise, and
* differentiate between interactive weight raising and
* soft real-time weight raising.
* *
* As a side note, it is worth considering that the above * As a side note, it is worth considering that the above
* device-idling countermeasures may however fail in the * device-idling countermeasures may however fail in the
...@@ -3592,7 +3597,8 @@ static bool bfq_better_to_idle(struct bfq_queue *bfqq) ...@@ -3592,7 +3597,8 @@ static bool bfq_better_to_idle(struct bfq_queue *bfqq)
* to let requests be served in the desired order until all * to let requests be served in the desired order until all
* the requests already queued in the device have been served. * the requests already queued in the device have been served.
*/ */
asymmetric_scenario = bfqq->wr_coeff > 1 || asymmetric_scenario = (bfqq->wr_coeff > 1 &&
bfqd->wr_busy_queues < bfqd->busy_queues) ||
!bfq_symmetric_scenario(bfqd); !bfq_symmetric_scenario(bfqd);
/* /*
......
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